Respuesta :

The first fraction divided by the second fraction is equivalent as multiplying the inverse of the second fraction

So the numerator in total will be: (a-4)(a+3)^2(a-1)

Denominator: 2(a^2 - a)(a-4) = 2a(a-1)(a-4)

Then, the same factor of numerator and denominator will be canceled out:

which are: (a-4)(a-1)

So the final answer:(a+3)^2 / 2a
=a^2+6a+9÷2a should be the answer
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