Question

How many liters of water must be added to 5.40 g of sodium nitrate to create a solution that has a concentration of 3.81 g/L?

Answer 1

Hey there !

Mass of solute = 5.40 g

Concentration = 3.81 g/L

Volume =  ?

therefore :

C = m / V

3.81 = 5.40 / V

V = 5.40 / 3.81

V = 1.417 L

Answer 2

Answer: The volume of water that must be added will be 1.417 L.

Explanation:

Concentration of a substance is defined as mass of solute (in grams) present in the given volume of a solution (in L).

The equation representing concentration is given as:

$\text{Concentration of solute}=\frac{\text{Mass of solute}}{\text{Volume of solvent}}$

We are given:

Concentration = 3.81 g/L

Mass of sodium nitrate = 5.40 g

Putting values in above equation, we get:

$3.81g/L=\frac{5.40g}{\text{Volume of water}}\\\\\text{Volume of water}=1.417L$

Hence, the volume of water that must be added will be 1.417 L.