Question

The volume of a gas with a pressure of 1.2 atm increases from 1.0 l to 4.0 l. what is the final pressure of the gas, assuming constant temperature? tip: use boyle's law

Answer 1

Pi x Vi = Pf x Vf which is Boyle's law

Answer 2

Answer:

Final pressure of he gas is 0.3 atm.

Explanation:

It is given that,

Initial pressure of the gas, P₁ = 1.2 atm

Initial volume of the gas, V₁ = 1 L

Final volume of the gas, V₂ = 4 L

We need to find the final pressure of the gas. It can be calculated using Boyle's law as :

$P_1V_1=P_2V_2$

$P_2=\dfrac{P_1V_1}{V_2}$

$P_2=\dfrac{1.2\ atm\times 1\ L}{4\ L}$

$P_2=0.3\ atm$

So, the final pressure of the gas at constant temperature is 0.3 atm. Hence, this is the required solution.