Respuesta :
Consider the figure attached.
Let m(R)=α degrees and m(T)=β degrees.
1.
Angle R, is an inscribed angle, intercepting the arc WTS.
This means that the measure of the arc WTS is double the measure of the angle R,
so m(arc WTS) = 2α degrees.
2.
Similarly,
Angle T, is an inscribed angle, intercepting the arc WRS. So
m(arc WRS) = 2β degrees.
3.
m(arc WTS)+m(arc WRS)=360° since these arcs cover the whole circle.
thus
2α+2β=360°
divide by 2:
α+β=180°
this means T and R are supplementary angles.
Let m(R)=α degrees and m(T)=β degrees.
1.
Angle R, is an inscribed angle, intercepting the arc WTS.
This means that the measure of the arc WTS is double the measure of the angle R,
so m(arc WTS) = 2α degrees.
2.
Similarly,
Angle T, is an inscribed angle, intercepting the arc WRS. So
m(arc WRS) = 2β degrees.
3.
m(arc WTS)+m(arc WRS)=360° since these arcs cover the whole circle.
thus
2α+2β=360°
divide by 2:
α+β=180°
this means T and R are supplementary angles.

Answer:
Step-by-step explanation:
Arc STR measures twice the measure of angle R, and arc WRS measures twice the measure of angle T.
STR = 2 x ∠R and WRS = 2 x ∠T --- This is because of the Inscribed Angle Theorem
If the measure of arcs STR and WRS are added together, the total would be 360° since a full circle is made up of 360°.
So mSTR + mWRS = 360°
Substituting the angle measures of R and T in for the arcs, the equation becomes:
2 • ∠R + 2 • ∠T = 360°
Simplifying further:
2 • [∠R + ∠T] = 360°
∠R + ∠T = 360° / 2
∠R + ∠T = 180° - This proves that opposite angles of a quadrilateral inscribed in a circle are supplementary.