(1) Area of the whole circle:
A = πr²
Substitute the value of BA to r,
A = (π)(10 ft)² = 314.16 ft²
(2) Area of the sector is calculated through the equation,
As = πr²(x/360°)
where x is the intercepted angle. Substituting the values,
As = π(10 ft)²(60°/360°) = 52.36 ft²
(3) Area of the equilateral triangle BAJ,
At = (√3)(a2²/4
where a is also equal to r or BA. Substituting,
At = (√3)(10 ft)²/4 = 43.30 ft²
The area of the region not shaded is equal to,
= (A) - (As - At)
Substituting,
= (314.16 ft²) - (52.36 ft² - 43.30 ft²)
Area = 305.10 ft²
Therefore, the answer to this answer is letter D.