Question

4 NH3 + 6 NO → 5 N2 + 6 H2O. How many moles of NO are required to completely react with 2.45 mol NH3? Show all of your work as well as the answer with the proper units.

Answer 1

6 mol NO - 4 mol NH₃
x mol NO - 2.45 mol NH₃

x=2.45*6/4=3.675≈3.68 mol

Answer 2

Mole is equal to the Avogadro's constant. The 3.675 moles of NO is required to completely react with 2.45 mole of Ammonia.    

Mole:

One mole is the unit of measurement of small particles like ions, atoms , and molecules. It is equal to the Avogadro's constant.

Given reaction,

$\bold{4 NH_3 + 6 NO \rightarrow5 N_2 + 6 H_2O}$

Means 4 moles of Ammonia react with 6 moles of NO in reaction. the molar ratio of ammonia and NO is 4:6.

Hence,

Moles of NO required

$\Rightarrow\bold{\frac{6}{4} \times 2.45 = 3.675 mole}$          

Hence, we can conclude that the 3.675 moles of NO is required to completely react with 2.45 mole of Ammonia.    

To know more about mole, you can refer to the link:

https://brainly.com/question/20486415