To solve this problem, we can use the following ratio formulas to find for the coordinates of the club house:
x = [m / (m + n)] (x2 – x1) + x1
y = [m / (m + n)] (y2 – y1) + y1
Where,
m and n are the ratios (0.5 and 0.5 each since the club house are to be located exactly halfway)
x1 and y1 are the x and y coordinates of the 1st pool (-16, -25)
x2 and y2 are the x and y coordinates of the 2nd pool (18, 23)
Substituting:
x = [0.5 / (0.5 + 0.5)] (18 - -16) + -16
x = 1
y = [0.5 / (0.5 + 0.5)] (23 - -25) + -25
y = -1
Therefore the club house should be located at coordinates (1, -1).