Mr. Rifkin had 240 digital and manual cameras. After donating 82 digital cameras and 26 manual cameras, he had 3 times as many digital cameras as manual cameras left. How many digital cameras did he have first?

Respuesta :

Using a system of equations, it is found that he had 181 digital cameras at first.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

  • Variable x: Number of digital cameras.
  • Variable y: Number of manual cameras.

Initially, there was of total of 240 digital and manual cameras, hence:

x + y = 240 -> y = 240 - x.

After donating 82 digital cameras and 26 manual cameras, he had 3 times as many digital cameras as manual cameras left, hence:

x - 82 = 3(y - 26).

Since y = 240 - x:

x - 82 = 3(y - 26)

x - 82 = 3(240 - x - 26)

x - 82 = -3x + 642

4x = 724.

x = 724/4

x = 181.

Hence, he had 181 digital cameras at first.

More can be learned about a system of equations at https://brainly.com/question/24342899

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