Question

A plane travel from California and back it took one hour long on the way out than it did on the way back the planes average speed was 300 miles an hour the average speed on the way back with 350 miles an hour how many hours did the trip take

Answer 1

recall your d = rt, distance = rate * time

the distance the plane travelled over and back was the same distance, say "d", since it simply went over to that city and then it came back from it.

if it took say "t" hours to come back, on the way over, it took then " t + 1 ", because it took longer on the way out by 1 hour.

and we know the speed rates.... ok

$\bf \begin{array}{lccclll} &distance&rate&time\\ &-----&-----&-----\\ \textit{going out}&d&300&t+1\\ \textit{coming back}&d&350&t \end{array} \\\\\\ \begin{cases} \boxed{d}=300(t+1)\\ d=350t\\ ----------\\ \boxed{300(t+1)}=350t \end{cases}$

solve for "t" to see how many hours it took on the way back.

the whole trip took then (t + 1) + t