Question

Enrique weighs 5 pounds more than twice Brendan's weight. If their total weight is 225 pounds, how much does Enrique weigh?

Answer 1

Hello!

We know that their total weight is 225, so we know that's on one side of the equation, alone. 

We have 225. 
B (Brendon's weight) + E (Enrique's weight)=225

We know that Enrique weighs 5 pounds more than twice Brendan's weight. 

So Enrique's weight is

E = 5 + 2B (5 more pounds than twice Brendan's weight)

So now we plug the E into our first equation. 

B + (5 + 2B) = 225

Simplify. 

3B + 5 = 225

Subtract 5 from both sides. 

3B = 220

Divide by 3

B = 73.3

Now we'll plug E and B into the initial equation to see if we're correct. 

73.3 + [5 + 2(73.3)] = 225

Simplify

73.3 + (5 + 146.7) = 225

So Yes, based on what we have done, Brendan weighs 73.3 pounds, and Enrique weighs 151.7 pounds. 

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Answer 2

Enrique's weight is 151.7 pounds.

What is Enrique's weight?

The sum of  Enrique and Brendan's weight is 225 pounds.

Let x represent  Brendan's weight.

Enrique's weight = 5 + 2x

5 + 2x + x = 225

5 + 3x = 225

3x = 225 - 5

3x = 220

220 / 3

x = 73.3

Enrique's weight = (73.3) x 2 + 5 = 151.7

To learn more about division, please check: https://brainly.com/question/194007