How many possible 10-digit phone numbers with the area code 617 are there? (any decimal digit can be the digit of a phone number. For instance the number 617−000−0000 is a possible phone number)

If all digits are possible and we are restricted to the 617 area code, then there are:

10^7 possible numbers

Because each digit can have 10 possible values from 0 through 9, you get

10*10*10*10*10*10*10 which is just 10^7

10,000,000 (ten million)

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aac271 aac271 · Answer 2 · 2021-07-14T21:22:09+02:00

Answer:

10,000,000

This is the answer because you have to do 10^7 because 3 of ten dights are filled so you have seven dights remaining. And yeah, i already checked it in my homework thingy fir RSM cuz I had the same problem. So yeah. I hope everyone who sees this has a lovely and beautiful day.

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