Question

find two consecutive even integers such that the smaller added to five times the larger give you a sum of 46.

Answer 1

First consecutive integer: n 
Second consecutive integer: n + 2 (next even integer) 
n + 5(n + 2) = 46 
n + 5n + 10 = 46 

6n + 10 = 46 
6n = 36 
n = 6 
n + 2 = 8 
Your answer is 6 and 8