Question

How many moles of hydrogen gas (h2) would be produced from the reaction of 0.30 moles of water (h2o) and excess sodium? (na)?

Answer 1

2Na + 2H₂O → 2NaOH + H₂

2 mol H₂O - 1 mol H₂
0.30 mol H₂O - x mol H₂

x=0.30*1/2= 0.15 mol