Respuesta :
The buoyant force is represented by the weight of the air which is displaced by the body.
The weight of the displaced air can be calculated using the following rule:
weight of displaced air = (density)(volume)(gravitational force)
where "volume" is the volume of the body (the man in our case) and density is the density of air (= 1000 kg/m^3)
So, we need to calculate the volume of the man:
weight = gravitational force x volume
700 n = 9.8 x volume
Therefore, volume of man = 71.428 m^3
Substituting with this volume along with the gravitational force and density in the above equation, we can calculate the buoyant force as follows:
buoyant force = weight of air displaced = (1000)(71.428)(9.8)
= 669.9944 x 10^3 n
The weight of the displaced air can be calculated using the following rule:
weight of displaced air = (density)(volume)(gravitational force)
where "volume" is the volume of the body (the man in our case) and density is the density of air (= 1000 kg/m^3)
So, we need to calculate the volume of the man:
weight = gravitational force x volume
700 n = 9.8 x volume
Therefore, volume of man = 71.428 m^3
Substituting with this volume along with the gravitational force and density in the above equation, we can calculate the buoyant force as follows:
buoyant force = weight of air displaced = (1000)(71.428)(9.8)
= 669.9944 x 10^3 n
Buoyant force due to the surrounding air on a man is 0.84 Newton
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Further explanation
The basic formula of pressure that needs to be recalled is:
Pressure = Force / Cross-sectional Area
or symbolized:
[tex]\large {\boxed {P = F \div A} }[/tex]
P = Pressure (Pa)
F = Force (N)
A = Cross-sectional Area (m²)
Let us now tackle the problem !
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Given:
Density of Air = ρ_air = 1.20 kg/m³
Weight of the man = w = 700 N
Density of the man = ρ = 1000 kg/m³
Asked:
Buoyant Force = F = ?
Solution:
We will use Archimedes' principle to solve the problem as follows:
[tex]F = \rho_{air} g V[/tex]
[tex]F = \rho_{air} g \frac{m}{\rho}[/tex]
[tex]F = \rho_{air} g \frac{w}{g\rho}[/tex]
[tex]F = \rho_{air} \frac{w}{\rho}[/tex]
[tex]F = 1.20 \times \frac{700}{1000}[/tex]
[tex]F = 0.84 \texttt{ Newton}[/tex]
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Learn more
- Minimum Coefficient of Static Friction : https://brainly.com/question/5884009
- The Pressure In A Sealed Plastic Container : https://brainly.com/question/10209135
- Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454
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Answer details
Grade: High School
Subject: Physics
Chapter: Pressure
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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant , Liquid , Pressure
