Question

The midpoint of a line with the endpoints (-2, 0) and (-6, 8) is:

(4, 4).
(-4, 4).
(-4, -4).
(4, -4).

Answer 1

midpoint is (x1 + x2)/2 , (y1 + y2)/2
(-2,0)...x1 = -2 and y1 = 0
(-6,8)...x2 = -6 and y2 = 8
now we sub and solve
m = (-2 +(-6) / 2 , (8 + 0)/2
m = (-2 - 6)/2 , 8/2
m = -8/2 , 8/2
m = (-4,4) <==