Question

Grade 12 data!!


18% of a population eats yogurt daily. What is the probability that, in a group of 10 people, 4 of them eat yogurt daily?
0.0032 0.072 0.067 0.00032

Answer 1

my opinion is 0.0032 hope it helps

Answer 2

Answer:

The probability that, in a group of 10 people, 4 of them eat yogurt daily is 0.067

Step-by-step explanation:

In this case we can apply a Binomial distribution in which there are n events and every event have a probability p to get a success. Then, the probability of x is:

$P(x)=nCx*p^{x}*(1-p)^{n-x}$

Where x is the number of people who eat yogurt daily, n is the total number of people and p is the probability of eats yogurt daily.

Additionally nCx is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

So, for the question we know that:

n=10

p=0.18

x=4

Replacing this values on the equation, we get:

$P(4)=10C4*0.18^{4}*(1-0.18)^{10-4}$

P(4)=0.067

Finally, the probability that, in a group of 10 people, 4 of them eat yogurt daily is 0.067