Respuesta :
8x - 5 ≥ 27
8x ≥ 32 <-- Add 5 to both sides
x ≥ 4 <-- Divide both sides by 8
So, to be in solution set, x has to be greater or equal to 4.
In interval notation: [4, ∞)
In a set builder notation: {x | x ∈ R, x ≥ 4}
8x ≥ 32 <-- Add 5 to both sides
x ≥ 4 <-- Divide both sides by 8
So, to be in solution set, x has to be greater or equal to 4.
In interval notation: [4, ∞)
In a set builder notation: {x | x ∈ R, x ≥ 4}