Question

Write the complete balanced equation for the following reaction: Na2SO4 + Pb(NO3)2 -->NaNO3 + PbSO4

Answer 1

Na2SO4 + Pb(NO3)2 --> NaNO3 + PbSO4
Na2SO4 + Pb(NO3)2 --> 2NaNO3 + PbSO4

(i'm not sure if you need to add the forms of the compounds as well)

Answer 2

Explanation:

A reaction equation that shows same number of atoms on both reactant and product sides is known as a balance equation.

$Na_{2}SO_{4} + Pb(NO_{3})_{2} \rightarrow NaNO_{3} + PbSO_{4}$

Number of atoms on reactant side are as follows.

Na = 2

$SO_{4}$ = 1

Pb = 1

$NO_{3}$ = 2

Number of atoms on product side are as follows.

Na = 1

$SO_{4}$ = 1

Pb = 1

$NO_{3}$ = 1

Therefore, to balance this chemical equation we multiply $NaNO_{3}$ by 2 on product side. Thus, we can conclude that the balanced chemical equation will be as follows.

            $Na_{2}SO_{4} + Pb(NO_{3})_{2} \rightarrow 2NaNO_{3} + PbSO_{4}$