Answer:
Range: [-2, 2] {y | -2 ≤ y ≤ 2}
Step-by-step explanation:
The given function is y = 2sinx
We have to find the range of the given function.
Since at y-axis sine function has the variance between -1 to 1 so range of y = sinx is [-1, 1]
and if the amplitude of sine function is 2 then sine function will vary from -2 to 2 which implies that range of y = 2 sinx will be [-2, 2]
So range of y = 2sinx is [-2, 2]
The range of the function y=2sin x is mathematically given as
dy=(-2,2)
Question Parameter(s):
function y=2sin x
Generally, the equation for the wave is mathematically given as
[tex]y(x,t)=Asin(kx−wt+\phi)[/tex]
Therefore, Comparing both equations
y(x,t)=Asin(kx−wt+\phi)
y=2sin x
We have
A=2
In conclusion, The range of a function y=2sin x is simply defined as the probable outcomes, with x values as independent factors.
Hence, with sinx having min and max values at (-1,1)
The y value range will be
dy=(2(-1),2(1))
dy=(-2,2)
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