The area of an artist's square canvas can hold 113 square inches of paint. What is the approximate length of one side of the canvas? (Approximate to the nearest hundredth inch.)

10.62 inches
10.63 inches
10.64 inches
10.65 inches

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irspow
The area of any rectangle is:

A=xy, and a square is just a special rectangle where the two dimensions are equal.  x=y=s, where s is the side length so the area of a square is:

A=s^2  we want to solve for s so

s^2=A

s=√A, and we are told that the area is 113 in^2

s=√113 in

s≈10.63 in (to nearest hundredth of an inch)

The area of the square canvas is the square of its side length

The length of the side of the square canvas is 10.63 inches

The area the square canvas can hold is given as:

[tex]Area=113in^2[/tex]

The canvas has a square as its shape, and the area of a square is:

[tex]Area = L^2[/tex]

Where:

L represents the length of the shape (i.e. the square canvas)

So, we have:

[tex]L^2 = 113[/tex]

Take square roots of both sides

[tex]L = \sqrt{113[/tex]

Take the square root of 113

[tex]L = 10.63[/tex]

Hence, the length of the side is 10.63 inches

Read more about areas at:

https://brainly.com/question/24487155

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