for option D, x²-9,
if you apply the identity[(a²-b²)=(a+b)(a-b)] it will give you (x+3)(x-3)=0,
here two things are possible if (x-3)is the zero,3 I.e. x=3, then the equation is true
or
(x+3) is 0, I.e. x=-3.
And rest of the equation don't have real roots!