Question

Which of the following quadrilaterals have diagonals that are perpendicular to each other? Check all that apply.

A. Rectangle
B. Square
C. Parallelogram
D. Rhombus

Answer 1

Answer:

B. Square

D. Rhombus

Step-by-step explanation:

If you take a rhombus ABCD, its all sides are congruent. Lets take E as the point where the diagonals of a rhombus meet. Now it is known fact that the point where diagonals meet, they bisect each other.

Since, for sides, AB , CD,AD and CB are congruent

For diagonals, AC = BD

As E is the bisecting point for diagonals,

AE = EC and ED = EB

Now by SSS postulate, we can prove that all four triangles formed by rhombus are congruent

ΔAED , ΔBEC , ΔEDC and ΔAEB are congruent

Now the angles

∠AED, ∠AEB, ∠CED and ∠CEB are congruent as well,

So, we know that sum of interior angles of any quadrilateral is 360°

So each angle is 360/4 = 90°

This calculation is valid for square as well.

Answer 2

Answer:

B. Square

D. Rhombus

Step-by-step explanation:

I just did it on A P E X