Question

A horse owner has 50 lbs of hay that is 6% protein by weight. He adds x lbs of oats that is 12% protein by weight.
The function y=.06(50)+.12x/50+x
models the percent of protein, y, in the final mixture of feed. What is the y-intercept of the function that models the percent of protein in the final mixture?
y-intercept=

Answer 1

Answer:

y-intercept = 0.06 = 6%

Step-by-step explanation:

As per the statement:

A horse owner has 50 lbs of hay that is 6% protein by weight. He adds x lbs of oats that is 12% protein by weight.

Given the function:

$y = \frac{0.06(50)+0.12x}{50+x}$

where, y represents the percent of protein in the final mixture of feed.

We have to find  y-intercept of the function that models the percent of protein in the final mixture.

Y-intercept:

Substitute x = 0 and solve for y:

then;

$y = \frac{0.06(50)+0.12(0)}{50+0}=\frac{0.60 \cdot 50}{50}$

⇒$y = 0.06 =6\%$

Therefore, the y-intercept of the function that models the percent of protein in the final mixture is, 6%

Answer 2

The y intercept of the final mixture made by the horse owner is 3.

Equation

An equation is an expression that is used to show the relationship between two or more numbers and variables.

Let y represent the percent of protein in x lbs of oat, hence:

y = (0.06(50) + 0.12x)

y = 0.12x + 3

The y intercept of the final mixture is 3.

Find out more on equation at: https://brainly.com/question/13763238