abbeygc1
abbeygc1
19-07-2017
Mathematics
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figure out 4x^2y^0/2y^-1
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Banabanana
Banabanana
19-07-2017
[tex] \cfrac{4x^2y^0}{2y^{-1}} = \cfrac{2x^2*1}{y^{-1}} =2x^2*y^1=2x^2y[/tex]
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