1) Neutralization equation:
HBr + NaOH --> NaBr + H2O
2) 1: 1 molar ratio => 1 mol NaOH neutralizez 1 mol HBr
3) M = n / V => n = M*V
=> M*V for NaOH = M*V for HBr
0.01888 l * 0.100M = x * 0.025 l => 0.01888 l * 0.10 M / 0.025 l = 0.0755 M
Answer: 0.0755 M