Question

ABC is a right triangle in which B is a right angle, AB= 1, AC=2 and BC= square root of 3. Cos C x sin A=

Answer 1

$cosC= sinA=\frac{BC}{AC}= \frac{ \sqrt{3} }{2} \\ \\ cosC*sinA=\left(\frac{ \sqrt{3} }{2}\right)^2= \frac{3}{4}=0.75$

Answer 2

Applying the cosine and sine ratios, the value of cos C × sin A = 3/4.

What is the Cosine and Sine Ratios?

Cosine ratio: cos ∅ = adj/hyp

Sine ratio: sin ∅ = opp/hyp.

Find cos C using the cosine ratio:

cos C = √3/2

Find sin A using the sine ratio:

sin A = √3/2

cos C × sin A = √3/2 × √3/2

= 3/4

cos C × sin A = 3/4

Learn more about the cosine and sine ratios on:

https://brainly.com/question/2920412

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