Question

1 2 3 4 5 6 7 8 9 10 TIME REMAINING 58:03 The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the standard form of the equation for this line?

Answer 1

(-5,-1)(10,-7)
slope = (-7 - (-1) / (10 - (-5) = -6 / 15 reduces to -2/5

y - y1 = m(x - x1)
slope(m) = -2/5
(10,-7)...x1 = 10 and y1 = -7
sub
y - (-7) = -2/5(x - 10) =
y + 7 = -2/5(x - 10)...point slope form

y + 7 = -2/5x + 4
y = -2/5x + 4 - 7
y = -2/5x - 3 ...slope intercept form
2/5x + y = -3
2x + 5y = -15 <== standard form