JanaeSpellman
JanaeSpellman
17-07-2017
Mathematics
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Why is the answer (A)?
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Banabanana
Banabanana
17-07-2017
[tex] \frac{1}{2}x^2+mx-5=0 \\ \\ x= \frac{-mб \sqrt{m^2-4* \frac{1}{2}*(-5) } }{2* \frac{1}{2} }= \frac{-mб \sqrt{m^2+10} }{1}=-mб \sqrt{m^2+10} [/tex]
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