Question

Given g(x) = 1.1845 - log x, determine for what value of x that g(x) = 1.

Answer 1

when no base is stated, assume base 10
and $log_a(b)=c$ translates to $a^c=b$

g(x)=1, hmm



1=1.1845-log x
times -1 both sides
-1=log x-1.1845
add 1.1845 to both sides
0.1845=log x
translate and assume base 10
$10^{0.1845}=x$
that's the exact value of x such that g(x)=1
you can evaluate it yourself