Question

When the following reaction is balanced the coefficient in front of carbon dioxide is: ____ C5H12 + ____ O2 → ____ CO2 + ____ H2O

Answer 1

Answer:

The coefficient of CO₂ is 5.

Explanation:

    Balancing the reaction:

___C₅H₁₂ + ___O₂ → ___CO₂ + ___H₂O

There are 5 C in the left side, so we put 5 on the right side:

___C₅H₁₂ + ___O₂ →  5CO₂ + ___H₂O

There are 12 H in the left side, so we put 6 as the coefficient of H₂O:

___C₅H₁₂ + ___O₂ →  5CO₂ + 6H₂O

Finally, there are 16 O in the right side, so we put 8 as the coefficient of O₂

___C₅H₁₂ + 8O₂ →  5CO₂ + 6H₂O

The coefficient of CO₂ is 5.

Answer 2

The coefficient in front of CO2 in the reaction: C5H12 + 8O2 → 5CO2 + 6H2O is 5.

BALANCING A CHEMICAL EQUATION:

• To balance a chemical reaction means to make sure that the number of atoms of each element on both sides of the equation is the same.

• To balance a chemical reaction, we make use of coefficients, which are numbers placed in front of the element.

• In the reaction given as follows: C5H12 + O2 → CO2 + H2O, the number of atoms of carbon, hydrogen, and oxygen are not equal on both sides of the equation.

• The balanced chemical equation is as follows: C5H12 + 8O2 → 5CO2 + 6H2O. This shows that the coefficient in front of carbon dioxide is 5.

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