Question

evaluate each function

Answer 1

I am going to give you all the answers after I explain how to answer these questions by yourself. Basically, just substitute the numbers into the function accordingly. 

For example, lets say I have the arbitrary function:

$f(x)=6x+2$

If I want to calculate$f(1)$ of that function, replace all $x$'s with 1. 

$f(1)=6(1)+2$
$=f(1)=6+2$
$=f(1)=8$

Done! Lets try calculating $f(2)$

$f(2)=6(2)+2$
$=f(2)=12+2$
$=f(2)=14$ 

Those are just some examples. There are many. Without further ado, here are the answers:


1)-2
2)4
3)10
4)-36
5)16
6)30
7)6
8)61

Thank you, and I hope that helped you. 

Answer 2

$1.\ \ p(n)=-3n^2+1\ \ \ \Rightarrow\ \ \ p(-1)=-3\cdot(-1)^2+1=-3+1=-2\\\\3.\ \ w(t)=t^3+2\ \ \ \Rightarrow\ \ \ w(2)=2^3+2=8+2=10\\ \\5.\ \ k(n)=n^2-4-n\ \ \ \Rightarrow\ \ \ k(5)=5^2-4-5=25-9=16\\ \\7.\ \ h(a)=a^2-5a\ \ \ \Rightarrow\ \ \ h(6)=6^2-5\cdot6=36-30=6$

$2.\ \ h(n)=2n^2+4\ \ \ \Rightarrow\ \ \ h(0)=2\cdot0^2+4=4\\ \\4.\ \ f(a)=-3a^2-3a\ \ \ \Rightarrow\ \ \ f(3)=-3\cdot 3^2-3\cdot3=-27-9=-36\\ \\6.\ \ f(a)=a^2-a\ \ \ \Rightarrow\ \ \ f(6)=662-6=36-6=30\\ \\8.\ \ p(n)=n^2-3\ \ \ \Rightarrow\ \ \ p(8)=8^2-3=64-3=61$