Question

Fiestaware is radioactive because the glaze used contains uranium oxide. the half-life of the uranium-238 isotope present in these dishes is about 4.5 billion years. this implies that most of the uranium-238 is still in the dishes and very little has decayed to emit ionizing radiation. uranium-238 initially decays into thorium-234 and an alpha particle as shown in the background, but thorium-234 can further decay to emit beta particles and gamma radiation. what is the decay reaction of thorium-234?

Answer 1

visit this page  and read the Radium series part
https://en.wikipedia.org/wiki/Uranium-238

Answer 2

Answer: The beta decay reaction of Th-234 is written above.

Explanation:

Beta decay is defined as the decay process in which a neutron gets converted to a proton and an electron. In this decay process, beta particle is emitted. The emitted particle carries a charge of -1 units and has a mass of 0 units.

The released beta particle is also known as electron.

The chemical equation for beta decay process of Th-234 follows:

$_{90}^{234}\textrm{Th}\rightarrow _{91}^{234}\textrm{Po}+_{-1}^0e^-+\gamma$

Hence, the beta decay reaction of Th-234 is written above.