Question

how do you solve \r+3=r-3 by the way / is a radical sign

Answer 1

Subtract three from both sides to get:

$\sqrt{r} =r-6$

Square both sides to get:

$r^2-12r+36=r$

Subtract r to get:
$r^2-13r+36=0$

Factor to get:
(r-9)(r-4)=0

The solutions to this equation are 9 and 4.