Question

need help parabola and its vertex

Answer 1

$y + 13 = 2(x - 1)^2$

use the equation: $(y_{2} - y_{1}) = m({x_{2} - x_{1})^2$

$(-11 + 13) = m(0 - 1)^2$

$2 = m(1)^2$

$m = 2$

$y + 13 = 2(x - 1)^2$

substitute y for 0, since x-intercepts occur on the x-axis, or the line y = 0 

$0 + 13 = 2(x - 1)^2$

$13 = 2(x - 1)^2$

$13 = 2(x^2 - 2x + 1)[tex] [tex]13 = 2x^2 - 4x + 2$

$2x^2 - 4x - 15$

use the quadratic equation (can't type it out on brainly, if you don't know, look it up)

$x = 1 - \sqrt{ \frac{13}{2} }, 1 + \sqrt{ \frac{13}{2} }$

The answer is: $(1 - \sqrt{ \frac{13}{2} },0)$ and $(1 + \sqrt{ \frac{13}{2} },0)$