Respuesta :
Let S=shortest side of the isosceles triangle.
Then length of the congruent sides are both S+1 units.
The perimeter is therefore the sum of all three sides
= S+(S+1)+(S+1)
=3S+2
Side length of square = S-2
Perimeter of square = 4(S-2) = 4S-8
Since the perimeter of square is the same as perimeter of isosceles triangle, we write
4S-8=3S+2
Isolate S and solve
4S-3S=2+8
S=10
Ans. the shortest length of the isosceles triangle is 10 units.
Then length of the congruent sides are both S+1 units.
The perimeter is therefore the sum of all three sides
= S+(S+1)+(S+1)
=3S+2
Side length of square = S-2
Perimeter of square = 4(S-2) = 4S-8
Since the perimeter of square is the same as perimeter of isosceles triangle, we write
4S-8=3S+2
Isolate S and solve
4S-3S=2+8
S=10
Ans. the shortest length of the isosceles triangle is 10 units.
Answer:
x= 10 just took the question and got it right
Step-by-step explanation: