Question

How many atoms of nitrogen are represented in 2(NH4)3PO4? (My answer: C)

2

3

6

12

Answer 1

yes you would be correct due to you must multiply the superscripts with the coefficients and 2*3 would get you six nitrogens.

Answer 2

Answer : The number of atoms of nitrogen present in $2(NH_4)_3PO_4$ are, 6.

Explanation :

The given compound is, $2(NH_4)_3PO_4$

The chemical name of this compound is, ammonium phosphate.

In this compound,

The number of nitrogen atoms = 6

The number of hydrogen atoms = 12

The number of phosphorous atoms = 2

The number of oxygen atoms = 8

Hence, the number of atoms of nitrogen present in $2(NH_4)_3PO_4$ are, 6.