Seudónimo
Seudónimo
27-04-2015
Mathematics
contestada
what are the complex solutions of 2x^2+x+6=0
Respuesta :
belcatya
belcatya
27-04-2015
lets use quadratic formula:
x=[tex] \frac{-1+- \sqrt{1-4*2*6} }{4}= \frac{-1+- \sqrt{-47} }{4}= \frac{-1+-i \sqrt{47} }{4} [/tex]
x₁=[tex]\frac{-1+i \sqrt{47} }{4} [/tex]
x₂=[tex]\frac{-1-i \sqrt{47} }{4} [/tex]
Answer Link
Panoyin
Panoyin
28-04-2015
2x² + x + 6 = 0
x =
-(1) +/- √((1)² - 4(2)(6))
2(2)
x =
-1 +/- √(1 - 48)
4
x =
-1 +/- √(-47)
4
x =
-1 +/- i√(47)
4
x =
-1 + i√(47)
x =
-1 - i√(47)
4 4
x = -0.25 + 0.25i√(47) x = -0.25 - 0.25i√(47)
Answer Link
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