Let vA = constant speed of car A, mph.
Let vB = constant speed of car B, mph.
After time t hours, car A reaches mile marker 10, so the time taken is
t = 10/vA.
At the same instant, car B reaches the mile marker 17, therefore
t = 17/vB = 10/vA
That is,
vA/vB = 10/17.
When car B reaches the mile marker 85, the time taken is
T = 85/vB.
At the same time, car A reaches the mile marker given by
x = T*vA = (85/vB)*vA = (vA/vB)*85.
Because vA/vB = 10/17, therefore
x = (10/17)*85 = 50.
When car B reaches the mile marker 85, car A reaches the mile marker 50.
Answer: 50