Respuesta :
Value of a
Segment PT and TR must have equal length. Therefore,
a + 4 = 2a
a = 4
Length of PR
PR = (a + 4) + 2a = (4 + 4) + 2(4)
PR = 16
Value of b
Segment QT and TS must have equal length. Therefore,
b = 2b – 3
b = 3
Length of QS
QS = b + (2b – 3) = 3 + (2*3 – 3)
QS = 6
Answer: a=4,b=3,PR=16 and QS=6
Step-by-step explanation: Since diagonals of parallelogram intersect each other into equal parts
i.e. a+4=2a and b=2b-3
i.e. a=4 and b=3
so, length of PR=a+4+2a
=3a+4
=3×4+4
=16
and length of QS=b+2b-3
=3b-3
=3×3-3
=6