Question

What is the energy in joules and ev of a photon in a radio wave from an am station that has a 1500 khz broadcast frequency?

Answer 1

E=hf
E=6.626e-34[Js]•1500e3[Hz]=9.939e-28[J]
For eV divide this by electron charge
9.939e-28[J]/1.6022e-19[C/e]=
6.203e-9eV