Question

How many grams of sodium chloride are present in a 0.75 M solution woth volume of 500.0 milliliters?

Answer 1

V = 500ml = 0,5 l
c = 0,75 M

c = n/V
n = c × V
n = 0,75 × 0,5 = 0,375[mol]

M NaCl = 58,5 g/mol

1 mol ------- 58,5 g
0,375 mol ----- x g

x = 0,375 mol × 58,5 g / 1 mol = 21,94 g

Answer: In this solution there are 21,94 g of sodium chloride.

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