1. Check the picture
2. Let S denote the siblings set, P denote the pets set.
let the intersection of P and S be x%
S is in total 75%, so the part (partition) only P not S is (75-x)%
Similarly the part only S not P is (25-x)%
3. [(75-x)+x+(20-x)+15]=100%
75-x+x+20-x+15=100
110-x=100
x=10
Answer : 10% of the students have both siblings and pets