Question

the vertex of the parabola is (-2,20) and the y-intercept is (0,-12)
what is the equation of the parabola?

Answer 1

f(x) = a(x-h)^2 + k

f(x) = a(x + 2)^2 + 20

-12 = a(0 + 2)^2 + 20
-12 = 4a + 20
-32 = 4a
-8 = a

f(x) = -8(x + 2)^2 + 20

y = -8x^2 - 32x - 12