Respuesta :
[tex]\bf \begin{array}{llllllllllllll}
64&+&81&+&100&+&121&+...\\\\
8^2&&9^2&&10^2&&11^2&...
\end{array}\implies \sum\limits_{n=8}^{\infty}\ n^2[/tex]
Answer: [tex]\sum_{n=8}^{\infty}n^2[/tex]
Step-by-step explanation:
The given series is [tex]64+81+100+121+...+n^2+...[/tex]
It can be seen that all the numbers are perfect square.
hence, the given series is of squares and it can be written as
[tex]8^2+9^2+10^2+11^2.......n^2+.....[/tex]
If we assuming the pattern continues till infinity , then by using summation the above series will be written as
[tex]8^2+9^2+10^2+11^2.......n^2+.....=\sum_{n=8}^{\infty}n^2[/tex]