Respuesta :
Recall that the volume of a regular prism is given by the area of the base times the height.
Given that the base of the prism is a regular pentagon with an apothem of 2.8 centimeters.
The pentagon consist of 5 isosceles triangles with the apothem as the height and the side of the pentagon as the base.
Recall that the are of a triangle is given by 1/2 base times height.
Thus the area of of the pentagon base of the prism is given by
[tex]Area= \frac{5}{2} x\times2.8=7x[/tex]
Therefore, the volume of the prism is given by
[tex]Volume=7x(2x+1)=14x^2+7x[/tex]
Given that the base of the prism is a regular pentagon with an apothem of 2.8 centimeters.
The pentagon consist of 5 isosceles triangles with the apothem as the height and the side of the pentagon as the base.
Recall that the are of a triangle is given by 1/2 base times height.
Thus the area of of the pentagon base of the prism is given by
[tex]Area= \frac{5}{2} x\times2.8=7x[/tex]
Therefore, the volume of the prism is given by
[tex]Volume=7x(2x+1)=14x^2+7x[/tex]
The expression that represents the volume of the prism is [tex]14x^2 + 7x[/tex]
The given parameters are:
- Apothem (a) = 2.8 cm
- Shape: Pentagon
Start, by calculating the area of the base of the prism using:
[tex]A = \frac 12 aln[/tex]
Where:
- n, represents the number of sides (n = 5)
- l, represents the length of each side (l = x)
So, we have:
[tex]A = \frac 12 \times 2.8 \times x \times 5[/tex]
[tex]A = 7x[/tex]
The volume of the prism is then calculated as:
[tex]V = Ah[/tex]
Where:
[tex]h =2x + 1[/tex]
So, we have:
[tex]A =7x \times (2x + 1)[/tex]
Expand
[tex]A =14x^2 + 7x[/tex]
Hence, the expression that represents the volume of the prism is [tex]14x^2 + 7x[/tex]
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