Respuesta :
Answer:
[tex]T=25d+\frac{3}{4}n+5c[/tex]
Step-by-step explanation:
A student earns a day to deliverer a newspaper= $25
She delivers for d days .
So she earns in d days = $25d
She also earns extra charges for each newspaper = $0.75 = [tex]\frac{3}{4}[/tex]
If she delivers n newspapers .
So. she earns extra charges for n newspapers = [tex]\frac{3}{4} n[/tex]
Now we are also given that She earns $5 for each new customer .
If she has c new customers .
So, she earns for c customers = $5c
So, her total earning = [tex]25d+\frac{3}{4}n+5c[/tex]
Let T denotes the total earning .
So, [tex]T=25d+\frac{3}{4}n+5c[/tex]
Thus Option 2 is correct.
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