Respuesta :
Hello.
Given the equation:
[tex]\mathsf{\boxed{5v + 1 = 21}}[/tex]
Testing for v = -7
[tex]\mathsf{5v + 1 = 21} \\
\\
\mathsf{5 \times (-7) + 1 = 21} \\
\\
\mathsf{-35 +1 = 21} \\
\\
\mathsf{-34 = 21}[/tex]
-34 does not equal 21. Therefore, '-7' is not a solution.
Hope I helped.
Given the equation:
[tex]\mathsf{\boxed{5v + 1 = 21}}[/tex]
Testing for v = -7
[tex]\mathsf{5v + 1 = 21} \\
\\
\mathsf{5 \times (-7) + 1 = 21} \\
\\
\mathsf{-35 +1 = 21} \\
\\
\mathsf{-34 = 21}[/tex]
-34 does not equal 21. Therefore, '-7' is not a solution.
Hope I helped.
Wym for "is -7 a solution"?
To plug for v? No, the value for v is 4.
21 = 5(4) + 1, check it. It's good! K?
To plug for v? No, the value for v is 4.
21 = 5(4) + 1, check it. It's good! K?
