Question

Find the width of the rectangle if it's area is (3x^2 + 9xy + 6y^2 ) square centimeters

3x + 6y cm is at the top of the rectangle p

Answer 1

the area of a rectangle is given by:
area=length*width
this implies that the width will be given by:
width=(area)/(length)
area=(3x^2+9xy+6y^2)
length=(3x+6y)
thus;
width=(3x^2+9xy+6y^2)/(3x+6y)
=[(3x+6y)(x+y)](3x+6y)
=(x+y) units