leeann514 leeann514
  • 30-06-2017
  • Mathematics
contestada

In △JKL, solve for x. 74.89 30.29 38.16 66.73

In JKL solve for x 7489 3029 3816 6673 class=

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Banabanana
Banabanana Banabanana
  • 30-06-2017
x = 34/cos27° = 34/0.891 ≈ 38.16
Answer Link
calculista
calculista calculista
  • 27-01-2019

Answer:

[tex]x=38.16\ units[/tex]

Step-by-step explanation:

we know that

In the right triangle JKL

[tex]cos(27\°)=\frac{KL}{JL}[/tex]

we have

[tex]KL=34\ units[/tex]

[tex]JL=x\ units[/tex]

substitute the values

[tex]cos(27\°)=\frac{34}{x}[/tex]

[tex]x=\frac{34}{cos(27\°)}=38.16\ units[/tex]

Answer Link

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