Respuesta :

Given a quadratic equation [tex] x^{2} +ax+c=0[/tex]

1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.

In our case the coefficient of x is 10, so we write 10 as 2*5

2. then we write + [tex] 5^{2} [/tex] and - [tex] 5^{2} [/tex] to the expression:

[tex] x^{2} +2*5*x+ 5^{2} -5^{2}+9=0[/tex]

[tex](x^{2} +2*5*x+ 5^{2}) -25+9=0[/tex]

[tex] (x+5)^{2}-16=0 [/tex]



Answer: [tex] (x+5)^{2}-16=0 [/tex]
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